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5-8m^2+3m=0
a = -8; b = 3; c = +5;
Δ = b2-4ac
Δ = 32-4·(-8)·5
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-13}{2*-8}=\frac{-16}{-16} =1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+13}{2*-8}=\frac{10}{-16} =-5/8 $
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